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31-40: BCBCABABBCThis is actually the Neco Gce 2018. Mathematics answers Answers as questions sent to our subscribers on WHATSAPP, if you are looking for 2020 WAEC/NECO Answers midnight before the exam, try contacting us.

41-50: DACCCCDBDB

**(10)**

**Draw the triangle **

**Hence we have A+B+C = 180**

**50+80+C = 180**

**130+C = 180**

**C = 180 - 130**

**C = 50**

**(i)**

**The bearing of B from C = 90 - 50 = 40°**

**(ii) **

**Bearing of A from B**

**90+50(alternate angle to A) **

**= 140°**

**(iii) **

**Distance between B and C**

**Using sine rule **

**C/sinC = a/SinA**

**40/sin50 = a/sin50**

**Cross multiply **

**asin50 = 40sin50**

**a = 40km**

**Hence distance between B and C = 40km**

**(iv) **

**Using cosine rule **

**b²= a²+c² - 2acCosB**

**where a = 40, c= 40 and B=80**

**b² = 40²+40² -2*40*40cos80**

**b² = 1600+1600 - 3200(0.1736)**

**b² = 3200 - 555.52**

**b² = 2644.48**

**b = âˆš2644.48**

**b = 51.42km**

**(v)**

**Height of Î”ABC**

**Draw the triangle **

**Area of the triangle **

**=1/2acSinB**

**=1/2*40*40sin80**

**=800(0.9848)**

**=787.84km²**

**Hence 1/2bh=787.84**

**bh=2*787.84**

**h=2*787.84/b**

**h=2*787.84/51.42**

**h=30.64**

**=31**

**(12)**

**TABULATE:**

**Marks | frq | c.f | boundary**

**11-20 | 8 | 8 | 10.5 â€“ 20.5**

**21-30 | 6 | 14 | 20.5 â€“ 30. 5**

**31-40 | 10 | 24 | 30.5 â€“ 40.5**

**41-50 | 12 | 36 | 40.5 â€“ 50.5**

**51-60 | 8 | 44 | 50.5-60.5**

**61-70 | 6 | 50 | 60.5 â€“ 70.5**

**(12b)**

**DRAW THE CUMULATIVE FREQUENCE CURVE**

**(12ci)**

**Medium mark = N + ½**

**= 50 + 1/2 = 51/2**

**= 25. 5**

**= 48**

**(12cii)**

**Lower quartile Q1**

**= ¼ x 50**

**= 12.5**

**= 28**

**(12ciii)**

**Upper quartile Q2**

**= ¾ x 50**

**= 37.5**

**=53**

**(12civ)**

**Both percentile **

**70/100 x 50 **

**= 35**

**= 50**

**====================================**

**(1) **

**TABULATE:**

**No| Log**

**3081| 3.4887**

**0.775 | 1.8893**

**0.456 | 1. 6589**

**| UNDER Log**

**| 3.4887**

**| 1. 5482**

**| 3.9405**

**| 0.9851**

**Square root of 4/3081/0.775.0456**

**Antilog = 9663**

**= 9.663**

**= 2.9**

**(2a)**

**1101â‚‚ = 2x + 1**

**1 x 2² + 0 x 2¹+ 1 x 2º = 2x + 1**

**8 + 4 + 1 = 2x +1**

**13 â€“ 2x**

**X = 12/2 = 6**

**(2b)**

**Sin x = 12/13 = 0.9231**

**Z = sin-¹ 0.9231 = 67.4º**

**Therefore 3 sin x + ½ cos x**

**= 3 sin 67.4 + ½ cos 67.4**

**= 3 x 0.9232 + ½ x 0.3843**

**= 7.7696 + 0.1921**

**(3a)**

**PQ x 90º [angle in a semicircle]**

**QPO = 90º - 62 [ angle in a triangle]**

**= 28º**

**Therefore POZ = 28º [alternative angles]**

**(ii)**

**PXZ = ½ x 28º = 14º [angle at center is twice angle at cirumfeence]**

**(3b)**

**6/5 + 3/x+3 â€“ 9/5(x+3)**

**= 6 (x+3) + 3 (5) â€“ 9/5(x+3)**

**= 6x + 18 + 15 â€“ 9/5 (x+3)**

**= 6x + 24/5(x+3) **

**= 6(x+4)/5(x+3)**

**(4a)**

**1/3(y-1)+2>1/2(2y-1)+1**

**2y-2+12>6y-3+1**

**2y-6y>-2-10**

**-4y>-12**

**y<3**

**(4bi)**

**M=y2-y1/X2-X1**

**=-1-2/2-3=-3/-1=3**

**(4bii)**

**2X+1=X+3**

**2X-X=3-1**

**X=2**

**(6)COMPLETED **

**(6)**

**126y = 86**

**1 x y² 2 x y¹ + 6 x yº = 86**

**y² + 2y + 6 = 86**

**y² + 2y + 6 â€“ 86 = 0**

**y² + 2y â€“ 80 = 0**

**y + 10y â€“ 8y â€“ 80 = 0**

**y (y+10)-8y (y+10) = 0 **

**y â€“ 8 = 0 or y + 10 = 0**

**the positive value of y**

**(6b) Area of triangle = ½ x b x h**

**Let the Acheal Area = x**

**Area = ½ x b x h**

**Base = x â€“ 9x/100 = 93/100**

**Height = 9x/100 + x = 107x/100**

**Area = ½ x 93x/100 x 107x/100**

**=963x/2000**

**% error = actual Area â€“ wrong/actual area x 100**

**= x â€“ 963x/2000 /x 100**

**= 20000x â€“ 963x/20000 x 100**

**= 19037/20000 x 100**

**= 95.185%**

**(6c)**

**p/100 + 2p + 7 = 11.02 x 100**

**p + 200p + 700 = 1102**

**201p = 1102 â€“ 700**

**201p = 402**

**P = 402/201**

**P = N2**

**P = 200K**

**(8)**

**S²â‚ (3x â€“ 1) (x+2) dx**

**By expansionâ€™**

**S²â‚ 3x² + 6x â€“ x â€“ 2 dx**

**S²â‚ 3x² + 5x â€“ 2 dx**

**By integrating using d formula**

**Xn+1/n+1**

**Therefore 3x ²+¹/2+1 + 5x¹+¹/1+1**

**= 2xº+¹/0+1 + c**

**Therefore 3x³/3 + 5x²/2 + 2x/1 + c**

**Therefore x³ + 5x²/2 + 2x**

**But x = 2 at higher and are at lower by substituting 2 in x than of value of 1**

**(2)³ + 5/2(2)² + 2(2) â€“ ((1)³ + 3/2(1) + 2 (1)**

**8 + 5/2 x 4 + 4 â€“ (1 + 5/2 + 2)**

**8 + 10 + 4 â€“ (3 + 5/2)**

**22 â€“ 11/2 = = 22-11/2**

**= 44- 11/2 **

**= 33/2**

**(8bi)**

**T = 2Ï€ square l/g**

**Dividing both side by 2Ï€**

**T/2Ï€ = square root of L/g**

**By squaring both side**

**(T/2 Ï€)² = (L/g)²**

**T²/4 Ï€² = l/g**

**Cross multiplication**

**gT²/T² = 4Ï€²L/T² **

**g = 4Ï€²L/T²**

**(8bii)**

**T = (0.4)1/2 = square root of 0.4**

**L = 0.04 T1 = 3.14**

**G = 4Ï€²L/T2 **

**= 4 x (3.14)² x 0.04/(0.4)²**

**= 4 x 9.8596 x 0.04/0.4 **

**= 1.578/0.4**

**g = 3.94**

**(9a)**

**2p-q=10.......(1)**

**3p+q^2=22........(2)**

**Eq(1) x3 and eq(2) x2**

**6p-3q=30**

**6p+2q=44**

**Subtracting eq(1) from eq(2)**

**-3q-2q= -14**

**2q^2+3q= 14**

**2q^2+3q-14=0**

**2q^2+7q-4q-14=0**

**q(2q+7)-2(2q+7)=0**

**(q-2)(2q+7)=0**

**q-2=0 or 2q+7=0**

**q=2 or q= -7/2**

**Substitute q into eq(1)**

**2p-q=10**

**2p-2=10**

**2p=10+2**

**2p=12**

**p=12/2=6**

**When q= -7/2**

**2p-q=10**

**2p-(-7/2)=10**

**2p+7/2=10**

**4p+7=10**

**4p=10-7**

**4p=3**

**p=3/4**

**(9b)**

**z^2 -25/z^2-9z+20**

**If Z is undefined **

**Z^2-9z+20=0**

**Using factorization method **

**-4z and -5z**

**Z^2 -4z-5z+20=0**

**Z(z-4) - 5(z-4)=0**

**(z-4)(z-5)=0**

**Z-4=0 or Z-5=0**

**Z=4 or Z=5**

**Z=4 or 5**

**Z is undefined when it is equal to 4 or 5**

**Answers loading.... **

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NECO seems less difficult compared to WAEC but not also easy to make A's.

waec expo runs is real. WAEC Answers, NECO ANSWERS and GCE answers comes a night before exam or Hours before exam

To register for NECO examination, candidates are to obtain a draft and pay a non-refundable fee of Twelve Thousand Naira Only (N12,000) paid via bank draft or to school management if internal registration. The payment can be done in any NECO office, banks and Nipost offices nationwide.

To register for NECO examination, candidates are to obtain a draft and pay a non-refundable fee of Twelve Thousand Naira Only (N12,000) paid via bank draft or to school management if internal registration. The payment can be done in any NECO office, banks and Nipost offices nationwide.Mar 26, 2020

Waec and neco are similar exams. ... They both test what you have been taught in secondary school. Therefore, you can use the same books, past questions and syllabus to prepare for both waec and neco.

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Similar to WAEC, your National Examination Council (NECO) result (certificate) is valid for life. It doesn't have any expiry date. That is, for as long as you live, you can use your NECO result to gain admission into the university and seek employment where applicable.

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Yes. You can gain admission into any institution in Nigeria with your NECO result. This is because, NECO is a national examination body, which is is responsible for conducting examination for students who are aspiring to further their education to tertiary level in Nigeria. ... They all accept NECO results in Nigeria.

Yes. You can gain admission into any institution in Nigeria with your NECO result. This is because, NECO is a national examination body, which is is responsible for conducting examination for students who are aspiring to further their education to tertiary level in Nigeria. ... They all accept NECO results in Nigeria.Jul 14, 2019

NECO SSCE External Candidates Original Result Slips Cost: The Sum of One Thousand Naira Only (N1,000). NECO SSCE External Candidates Issuance of Original Certificate Cost: The Sum of One Hundred Naira Only (N100).

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Yes, you can use NECO (be it NECO June/July or Nov/Dec) to gain admission into any university of your choice. Generally, all higher institutions accept NECO just like WAEC, GCE and NABTEB. You can as well combine your NECO with another NECO or any other exams type to gain admission.

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The fact is your O'level result; be it WAEC , NECO or NABTEB is valid for a life time and has no expiration date. The Examination conducted by these examination bodies is known as ?achievement test? and therefore the certificates awarded are valid forever.

We released SSCE results in 43 days ? NECO. The National Examinations Council has said it released the last Senior Secondary Certificate Examination results in 43 days.

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The answer is yes. NECO can be used to study abroad but not all schools abroad accept it. ... First of all, an applicant with a NECO result must sit for a proficiency English language exam such as GRE, IELTS, SAT, ACT, PSAT, TOEFL, GMAT, and the likes.

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